Visual Basic .NET Find a Word
From Regex Regular Expression Encyclopedia
You can use this recipe for finding single words in a block of text. The expression will find only complete words surrounded by spaces or other word delimiters, such as punctuation or the beginning or end of a line.
code
Imports System Imports System.IO Imports System.Text.RegularExpressions Public Class Recipe Private Shared _Regex As Regex = New Regex("\bsomething\b") Public Sub Run(ByVal fileName As String) Dim line As String Dim lineNbr As Integer = 0 Dim sr As StreamReader = File.OpenText(fileName) line = sr.ReadLine While Not line Is Nothing lineNbr = lineNbr + 1 If _Regex.IsMatch(line) Then Console.WriteLine("Found match '{0}' at line {1}", _ line, _ lineNbr) End If line = sr.ReadLine End While sr.Close() End Sub Public Shared Sub Main(ByVal args As String()) Dim r As Recipe = New Recipe r.Run(args(0)) End Sub End Class
How It Works
A special character class, \b, allows you to easily search for whole words. This is an advantage because without doing a whole bunch of extra work you can make sure that a search for some- thing, for example, doesn’t yield unexpected matches such as somethings. You can break the regular expression shown here into the following:
| Regular Expression | Description |
|---|---|
| \b | a word boundary (a space, beginning of a line, or punctuation) . . . |
| something | s, o, m, e, t, h, i, n, and g . . . |
| \b | a word boundary at the end of the word. |
This expression differs just slightly from the C# and Visual Basic .NET examples because the RegularExpressionValidator control assumes that the expression is to match the entire value (there’s an implied ^ at the beginning of the expression and $ at the end of the expres- sion). The combination .* has been added before and after the word boundary \b so the full word can float around inside the line.
